Maths - 2D Shapes
Author:Futoro Ltd
Professions
This tool will help calculate the area and circumference of shapes including: squares, triangles, circles and more.
1
²
4
0.5
²
1.064177772475912
1.1851303147331054
3.2493080872090174
3.141592653589793
²
6.283185307179586
General Help
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Maths - 2D Shapes Help
General
The shapes are divided into their types, square-like, triangular, round, etc.
For each there are tabs, e.g. the round shapes have: Circle, Ellipse and Arc tabs.
Some shapes will actively transform to reflect the users inputs, but as these values could be large we cannot represent all values. Therefore some shapes will grow/shrink accordingly only by a limited amount to ensure that the shape can still be represented visually. A good example of this is the Trapezoid which is very constrained as it would be very difficult to fully represent this shape on the small screen space used.
If a result is denoted by the symbol ≈ in the suffix column it means that the value is an approximation and should not be used for precision.
Every effort for correct results have been taken, but we cannot guarantee that we have done everything correctly. Please be careful when using these results on something that requires extreme accuracy.
You can click the buttons to copy the calculated value to the clipboard.
Square / Rectangle
The area equation we used is:
a = hw
The circumference equation we used is:c = 2(h + w)
Parallelogram
The area equation we used is:
a = hb
The circumference equation we used is:c = 2(s + b)
Trapezoid
The area equation we used is:
a = h
The circumference equation we used is:b + z
2
c = b + x + y + z
Triangle
The area equation we used is:
a =
The circumference equation we used is:bh
2
c = b + hyp + opp
Circle
The area equation we used is:
a = πr²
The circumference equation we used is:c = 2πr
Ellipse
The area equation we used is:
a = πab
Calculating the circumference for ellipsis can be difficult, we have used one of the equations created by the famous Indian mathematician Srinivasa Ramanujan.
The equation we used is:
c ≈ π(a+b) (1 +)
where:3h
10 + √(4-3h)
h =
(a - b)²
(a + b)²
As this is an approximation, the result is denoted by a ≈ symbol. See comment above.
Arc
The area equation we used is:
a = r²
The circumference equation we used is:θ
2
θ is in radians
c = rθ
θ is in radians